(9^4+x)(81^x)=1/3

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Solution for (9^4+x)(81^x)=1/3 equation: 



(9^4+x)(81^x)=1/3

We move all terms to the left:

(9^4+x)(81^x)-(1/3)=0

We add all the numbers together, and all the variables

(9^4+x)81^x-(+1/3)=0

We get rid of parentheses

(9^4+x)81^x-1/3=0

We multiply all the terms by the denominator


((9^4+x)81^x)*3-1=0

We move all terms containing x to the left, all other terms to the right

((9^4+x)81^x)*3=1

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